C++ Program to check if a Number Is Even or odd

Check if a Number is Even or odd in C++

Given an integer input, the objective is to write a code to Check if a Number is Even or odd in C Language.

For Instance,

Input: Num = -5

Output: The number is Negative

Check if a Number is Even or odd in C++

Given an integer input, the objective is to check whether the given integer is Even or odd. In order to do so we have the following methods:

Method 1: Using Brute Force
Method 2: Using Nested if-else Statements
Method 3: Using the ternary operator

C++ Program to Check Whether a Number is Even or Odd

Given an integer input, the objective is to write a C++ program to check whether a number is Even or Odd.

Method 1: Using Brute Force

#include <iostream>
using namespace std;
int main () {
    int number;
    cout << "Enter a number:"; 
    cin >> number;
    if (number % 2 == 0)
        cout << number << " : Even";
    else
        cout << number << " : Odd";
    return 0;
}

Output:

Enter a number: 4
4 : Even

Method 2: Using Ternary Operator

#include <iostream>
using namespace std;
int main () {
    int number;
    cout << "Enter a number:"; 
    cin >> number;
    number % 2 == 0 ? cout << "Even" : cout << "Odd";
    return 0;
}

Output:

Enter a number: 17
Odd

Method 3: Using Bitwise Operator

#include <iostream>
using namespace std;
bool isEven(int number) {
    return (!(number & 1));
}
int main() {
    int number;
    cout << "Enter the number: ";
    cin >> number;
    isEven(number) ? cout << "Even" : cout << "Odd";
    return 0;
}

Output:

Enter a number: 13
Odd